2(2c+7)-3c=7(c+5)

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Solution for 2(2c+7)-3c=7(c+5) equation: 



2(2c+7)-3c=7(c+5)

We move all terms to the left:

2(2c+7)-3c-(7(c+5))=0

We add all the numbers together, and all the variables

-3c+2(2c+7)-(7(c+5))=0

We multiply parentheses

-3c+4c-(7(c+5))+14=0



We calculate terms in parentheses: -(7(c+5)), so:

7(c+5)

We multiply parentheses

7c+35

Back to the equation:

-(7c+35)



We add all the numbers together, and all the variables

c-(7c+35)+14=0

We get rid of parentheses

c-7c-35+14=0

We add all the numbers together, and all the variables

-6c-21=0

We move all terms containing c to the left, all other terms to the right

-6c=21

c=21/-6

c=-3+1/2

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