2(2c+3)-4(c-4)=c+2(c+5)

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Solution for 2(2c+3)-4(c-4)=c+2(c+5) equation: 



2(2c+3)-4(c-4)=c+2(c+5)

We move all terms to the left:

2(2c+3)-4(c-4)-(c+2(c+5))=0

We multiply parentheses

4c-4c-(c+2(c+5))+6+16=0



We calculate terms in parentheses: -(c+2(c+5)), so:

c+2(c+5)

We multiply parentheses

c+2c+10

We add all the numbers together, and all the variables

3c+10

Back to the equation:

-(3c+10)



We add all the numbers together, and all the variables

-(3c+10)+22=0

We get rid of parentheses

-3c-10+22=0

We add all the numbers together, and all the variables

-3c+12=0

We move all terms containing c to the left, all other terms to the right

-3c=-12

c=-12/-3

c=+4

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