2(2c+1)=3(c-4)

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Solution for 2(2c+1)=3(c-4) equation: 



2(2c+1)=3(c-4)

We move all terms to the left:

2(2c+1)-(3(c-4))=0

We multiply parentheses

4c-(3(c-4))+2=0



We calculate terms in parentheses: -(3(c-4)), so:

3(c-4)

We multiply parentheses

3c-12

Back to the equation:

-(3c-12)



We get rid of parentheses

4c-3c+12+2=0

We add all the numbers together, and all the variables

c+14=0

We move all terms containing c to the left, all other terms to the right

c=-14

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