2(2b-1)=4(3b-2)

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Solution for 2(2b-1)=4(3b-2) equation: 



2(2b-1)=4(3b-2)

We move all terms to the left:

2(2b-1)-(4(3b-2))=0

We multiply parentheses

4b-(4(3b-2))-2=0



We calculate terms in parentheses: -(4(3b-2)), so:

4(3b-2)

We multiply parentheses

12b-8

Back to the equation:

-(12b-8)



We get rid of parentheses

4b-12b+8-2=0

We add all the numbers together, and all the variables

-8b+6=0

We move all terms containing b to the left, all other terms to the right

-8b=-6

b=-6/-8

b=3/4

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