2(2a+4b-c)-4(a-5b+3c)=

Solution for 2(2a+4b-c)-4(a-5b+3c)= equation:

Simplifying
2(2a + 4b + -1c) + -4(a + -5b + 3c) = 0
(2a * 2 + 4b * 2 + -1c * 2) + -4(a + -5b + 3c) = 0
(4a + 8b + -2c) + -4(a + -5b + 3c) = 0
4a + 8b + -2c + (a * -4 + -5b * -4 + 3c * -4) = 0
4a + 8b + -2c + (-4a + 20b + -12c) = 0

Reorder the terms:
4a + -4a + 8b + 20b + -2c + -12c = 0

Combine like terms: 4a + -4a = 0
0 + 8b + 20b + -2c + -12c = 0
8b + 20b + -2c + -12c = 0

Combine like terms: 8b + 20b = 28b
28b + -2c + -12c = 0

Combine like terms: -2c + -12c = -14c
28b + -14c = 0

Solving
28b + -14c = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '14c' to each side of the equation.
28b + -14c + 14c = 0 + 14c

Combine like terms: -14c + 14c = 0
28b + 0 = 0 + 14c
28b = 0 + 14c
Remove the zero:
28b = 14c

Divide each side by '28'.
b = 0.5c

Simplifying
b = 0.5c