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2(2a)(a=5)
We move all terms to the left:
2(2a)(a-(5))=0
We multiply parentheses
22a^2-110a=0
a = 22; b = -110; c = 0;
Δ = b2-4ac
Δ = -1102-4·22·0
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12100}=110$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-110)-110}{2*22}=\frac{0}{44} =0 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-110)+110}{2*22}=\frac{220}{44} =5 $
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