2(20-3x)=-10(9x-4)

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Solution for 2(20-3x)=-10(9x-4) equation: 



2(20-3x)=-10(9x-4)

We move all terms to the left:

2(20-3x)-(-10(9x-4))=0

We add all the numbers together, and all the variables

2(-3x+20)-(-10(9x-4))=0

We multiply parentheses

-6x-(-10(9x-4))+40=0



We calculate terms in parentheses: -(-10(9x-4)), so:

-10(9x-4)

We multiply parentheses

-90x+40

Back to the equation:

-(-90x+40)



We get rid of parentheses

-6x+90x-40+40=0

We add all the numbers together, and all the variables

84x=0

x=0/84

x=0

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