2(20+3c)=8

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Solution for 2(20+3c)=8 equation: 



2(20+3c)=8

We move all terms to the left:

2(20+3c)-(8)=0

We add all the numbers together, and all the variables

2(3c+20)-8=0

We multiply parentheses

6c+40-8=0

We add all the numbers together, and all the variables

6c+32=0

We move all terms containing c to the left, all other terms to the right

6c=-32

c=-32/6

c=-5+1/3

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