2(2-y)=3(y-4)

Solution for 2(2-y)=3(y-4) equation:

2(2-y)=3(y-4)

We move all terms to the left:

2(2-y)-(3(y-4))=0

We add all the numbers together, and all the variables

2(-1y+2)-(3(y-4))=0

We multiply parentheses

-2y-(3(y-4))+4=0


We calculate terms in parentheses: -(3(y-4)), so:

3(y-4)

We multiply parentheses

3y-12

Back to the equation:

-(3y-12)


We get rid of parentheses

-2y-3y+12+4=0

We add all the numbers together, and all the variables

-5y+16=0

We move all terms containing y to the left, all other terms to the right

-5y=-16

y=-16/-5

y=3+1/5