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2(2-5x)=3(2x+1)
We move all terms to the left:
2(2-5x)-(3(2x+1))=0
We add all the numbers together, and all the variables
2(-5x+2)-(3(2x+1))=0
We multiply parentheses
-10x-(3(2x+1))+4=0
We calculate terms in parentheses: -(3(2x+1)), so:We get rid of parentheses
3(2x+1)
We multiply parentheses
6x+3
Back to the equation:
-(6x+3)
-10x-6x-3+4=0
We add all the numbers together, and all the variables
-16x+1=0
We move all terms containing x to the left, all other terms to the right
-16x=-1
x=-1/-16
x=1/16
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