2(2+v)+v=3(v-1)+6

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Solution for 2(2+v)+v=3(v-1)+6 equation: 



2(2+v)+v=3(v-1)+6

We move all terms to the left:

2(2+v)+v-(3(v-1)+6)=0

We add all the numbers together, and all the variables

2(v+2)+v-(3(v-1)+6)=0

We add all the numbers together, and all the variables

v+2(v+2)-(3(v-1)+6)=0

We multiply parentheses

v+2v-(3(v-1)+6)+4=0



We calculate terms in parentheses: -(3(v-1)+6), so:

3(v-1)+6

We multiply parentheses

3v-3+6

We add all the numbers together, and all the variables

3v+3

Back to the equation:

-(3v+3)



We add all the numbers together, and all the variables

3v-(3v+3)+4=0

We get rid of parentheses

3v-3v-3+4=0

We add all the numbers together, and all the variables

1!=0

There is no solution for this equation

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