2(2+t)=2(2t-1)-8

Solution for 2(2+t)=2(2t-1)-8 equation:

2(2+t)=2(2t-1)-8

We move all terms to the left:

2(2+t)-(2(2t-1)-8)=0

We add all the numbers together, and all the variables

2(t+2)-(2(2t-1)-8)=0

We multiply parentheses

2t-(2(2t-1)-8)+4=0


We calculate terms in parentheses: -(2(2t-1)-8), so:

2(2t-1)-8

We multiply parentheses

4t-2-8

We add all the numbers together, and all the variables

4t-10

Back to the equation:

-(4t-10)


We get rid of parentheses

2t-4t+10+4=0

We add all the numbers together, and all the variables

-2t+14=0

We move all terms containing t to the left, all other terms to the right

-2t=-14

t=-14/-2

t=+7