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2(2+12)=x(x+6)
We move all terms to the left:
2(2+12)-(x(x+6))=0
We add all the numbers together, and all the variables
-(x(x+6))+214=0
We calculate terms in parentheses: -(x(x+6)), so:We get rid of parentheses
x(x+6)
We multiply parentheses
x^2+6x
Back to the equation:
-(x^2+6x)
-x^2-6x+214=0
We add all the numbers together, and all the variables
-1x^2-6x+214=0
a = -1; b = -6; c = +214;
Δ = b2-4ac
Δ = -62-4·(-1)·214
Δ = 892
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{892}=\sqrt{4*223}=\sqrt{4}*\sqrt{223}=2\sqrt{223}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{223}}{2*-1}=\frac{6-2\sqrt{223}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{223}}{2*-1}=\frac{6+2\sqrt{223}}{-2} $
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