2(1y+1)=8

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Solution for 2(1y+1)=8 equation: 



2(1y+1)=8

We move all terms to the left:

2(1y+1)-(8)=0

We add all the numbers together, and all the variables

2(y+1)-8=0

We multiply parentheses

2y+2-8=0

We add all the numbers together, and all the variables

2y-6=0

We move all terms containing y to the left, all other terms to the right

2y=6

y=6/2

y=3

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