2(11n-3)-12=3n+3(n+10)

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Solution for 2(11n-3)-12=3n+3(n+10) equation: 



2(11n-3)-12=3n+3(n+10)

We move all terms to the left:

2(11n-3)-12-(3n+3(n+10))=0

We multiply parentheses

22n-(3n+3(n+10))-6-12=0



We calculate terms in parentheses: -(3n+3(n+10)), so:

3n+3(n+10)

We multiply parentheses

3n+3n+30

We add all the numbers together, and all the variables

6n+30

Back to the equation:

-(6n+30)



We add all the numbers together, and all the variables

22n-(6n+30)-18=0

We get rid of parentheses

22n-6n-30-18=0

We add all the numbers together, and all the variables

16n-48=0

We move all terms containing n to the left, all other terms to the right

16n=48

n=48/16

n=3

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