2(11d+2)+5d=20d+4

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Solution for 2(11d+2)+5d=20d+4 equation: 



2(11d+2)+5d=20d+4

We move all terms to the left:

2(11d+2)+5d-(20d+4)=0

We add all the numbers together, and all the variables

5d+2(11d+2)-(20d+4)=0

We multiply parentheses

5d+22d-(20d+4)+4=0

We get rid of parentheses

5d+22d-20d-4+4=0

We add all the numbers together, and all the variables

7d=0

d=0/7

d=0

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