2(11+3k)=2+2(k+6)

Solution for 2(11+3k)=2+2(k+6) equation:

2(11+3k)=2+2(k+6)

We move all terms to the left:

2(11+3k)-(2+2(k+6))=0

We add all the numbers together, and all the variables

2(3k+11)-(2+2(k+6))=0

We multiply parentheses

6k-(2+2(k+6))+22=0


We calculate terms in parentheses: -(2+2(k+6)), so:

2+2(k+6)

determiningTheFunctionDomain
2(k+6)+2

We multiply parentheses

2k+12+2

We add all the numbers together, and all the variables

2k+14

Back to the equation:

-(2k+14)


We get rid of parentheses

6k-2k-14+22=0

We add all the numbers together, and all the variables

4k+8=0

We move all terms containing k to the left, all other terms to the right

4k=-8

k=-8/4

k=-2