2(10y-8)+3(6y+1)=4(y+1)

Solution for 2(10y-8)+3(6y+1)=4(y+1) equation:

2(10y-8)+3(6y+1)=4(y+1)

We move all terms to the left:

2(10y-8)+3(6y+1)-(4(y+1))=0

We multiply parentheses

20y+18y-(4(y+1))-16+3=0


We calculate terms in parentheses: -(4(y+1)), so:

4(y+1)

We multiply parentheses

4y+4

Back to the equation:

-(4y+4)


We add all the numbers together, and all the variables

38y-(4y+4)-13=0

We get rid of parentheses

38y-4y-4-13=0

We add all the numbers together, and all the variables

34y-17=0

We move all terms containing y to the left, all other terms to the right

34y=17

y=17/34

y=1/2