If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2(10x-52)=x+29
We move all terms to the left:
2(10x-52)-(x+29)=0
We multiply parentheses
20x-(x+29)-104=0
We get rid of parentheses
20x-x-29-104=0
We add all the numbers together, and all the variables
19x-133=0
We move all terms containing x to the left, all other terms to the right
19x=133
x=133/19
x=7
| 2(x+29)=10x-52 | | -3(5x+12)=-39 | | u+2/2=3 | | 2(2x-9=38 | | 4r+3r-r= | | x/7=28/63 | | -q+4=-9 | | -3(6c+7)=-15 | | 17-17a=6a+6(5a+8) | | r+1=-8 | | 4p-3=13-4p | | 11=x/4-8 | | u+2=9 | | 2x-5(-4)=-8+2x+18 | | -5a+4=3a-8a | | 2f−6=4 | | 7(8)-23=11x-1 | | 3u+10=70 | | 2(4w+5)=14 | | -2n-8)=-2 | | 14+k=k+2k | | 360=a90+133+68 | | -3=p+-11 | | 2x-8=50x= | | z−10=5 | | 77-9x=2x-7 | | -7(x=18)=-14 | | k-13=44 | | y3+9=15 | | t-13=42 | | x2-x+88=360 | | 8a-7=a+9 |