2(10x-27)=2(2x+29)

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Solution for 2(10x-27)=2(2x+29) equation: 



2(10x-27)=2(2x+29)

We move all terms to the left:

2(10x-27)-(2(2x+29))=0

We multiply parentheses

20x-(2(2x+29))-54=0



We calculate terms in parentheses: -(2(2x+29)), so:

2(2x+29)

We multiply parentheses

4x+58

Back to the equation:

-(4x+58)



We get rid of parentheses

20x-4x-58-54=0

We add all the numbers together, and all the variables

16x-112=0

We move all terms containing x to the left, all other terms to the right

16x=112

x=112/16

x=7

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