2(10-c)=3(c+5)

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Solution for 2(10-c)=3(c+5) equation: 



2(10-c)=3(c+5)

We move all terms to the left:

2(10-c)-(3(c+5))=0

We add all the numbers together, and all the variables

2(-1c+10)-(3(c+5))=0

We multiply parentheses

-2c-(3(c+5))+20=0



We calculate terms in parentheses: -(3(c+5)), so:

3(c+5)

We multiply parentheses

3c+15

Back to the equation:

-(3c+15)



We get rid of parentheses

-2c-3c-15+20=0

We add all the numbers together, and all the variables

-5c+5=0

We move all terms containing c to the left, all other terms to the right

-5c=-5

c=-5/-5

c=1

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