2(10-2b)=4(2b+2)

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Solution for 2(10-2b)=4(2b+2) equation: 



2(10-2b)=4(2b+2)

We move all terms to the left:

2(10-2b)-(4(2b+2))=0

We add all the numbers together, and all the variables

2(-2b+10)-(4(2b+2))=0

We multiply parentheses

-4b-(4(2b+2))+20=0



We calculate terms in parentheses: -(4(2b+2)), so:

4(2b+2)

We multiply parentheses

8b+8

Back to the equation:

-(8b+8)



We get rid of parentheses

-4b-8b-8+20=0

We add all the numbers together, and all the variables

-12b+12=0

We move all terms containing b to the left, all other terms to the right

-12b=-12

b=-12/-12

b=1

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