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2(1/5)x-5=2(1(2/5)x+3)
We move all terms to the left:
2(1/5)x-5-(2(1(2/5)x+3))=0
Domain of the equation: 5)x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 5)x+3))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2(+1/5)x-(2(1(+2/5)x+3))-5=0
We multiply parentheses
2x^2-(2(1(+2/5)x+3))-5=0
We multiply all the terms by the denominator
2x^2*5)x+3))-(2(1(-5*5)x+3))+2=0
We add all the numbers together, and all the variables
2x^2*5)x+3))-(2(1(-25)x+3))+2=0
Wy multiply elements
10x^3-25)x+3))+2=0
We do not support expression: x^3
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