2(1/2q+1)=-3(2q-1)+4(2q-1)+4(2q+1)

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Solution for 2(1/2q+1)=-3(2q-1)+4(2q-1)+4(2q+1) equation: 



2(1/2q+1)=-3(2q-1)+4(2q-1)+4(2q+1)

We move all terms to the left:

2(1/2q+1)-(-3(2q-1)+4(2q-1)+4(2q+1))=0



Domain of the equation: 2q+1)!=0

q∈R



We multiply parentheses

2q-(-3(2q-1)+4(2q-1)+4(2q+1))+2=0



We calculate terms in parentheses: -(-3(2q-1)+4(2q-1)+4(2q+1)), so:

-3(2q-1)+4(2q-1)+4(2q+1)

We multiply parentheses

-6q+8q+8q+3-4+4

We add all the numbers together, and all the variables

10q+3

Back to the equation:

-(10q+3)



We get rid of parentheses

2q-10q-3+2=0

We add all the numbers together, and all the variables

-8q-1=0

We move all terms containing q to the left, all other terms to the right

-8q=1

q=1/-8

q=-1/8

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