2(1/2q+1)=-3(2q-1)+10+4(2q+1)

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Solution for 2(1/2q+1)=-3(2q-1)+10+4(2q+1) equation: 



2(1/2q+1)=-3(2q-1)+10+4(2q+1)

We move all terms to the left:

2(1/2q+1)-(-3(2q-1)+10+4(2q+1))=0



Domain of the equation: 2q+1)!=0

q∈R



We multiply parentheses

2q-(-3(2q-1)+10+4(2q+1))+2=0



We calculate terms in parentheses: -(-3(2q-1)+10+4(2q+1)), so:

-3(2q-1)+10+4(2q+1)

determiningTheFunctionDomain
-3(2q-1)+4(2q+1)+10

We multiply parentheses

-6q+8q+3+4+10

We add all the numbers together, and all the variables

2q+17

Back to the equation:

-(2q+17)



We get rid of parentheses

2q-2q-17+2=0

We add all the numbers together, and all the variables

-15!=0

There is no solution for this equation

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