2(1/2b-6)+3b=12

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Solution for 2(1/2b-6)+3b=12 equation: 



2(1/2b-6)+3b=12

We move all terms to the left:

2(1/2b-6)+3b-(12)=0



Domain of the equation: 2b-6)!=0

b∈R



We add all the numbers together, and all the variables

3b+2(1/2b-6)-12=0

We multiply parentheses

3b+2b-12-12=0

We add all the numbers together, and all the variables

5b-24=0

We move all terms containing b to the left, all other terms to the right

5b=24

b=24/5

b=4+4/5

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