2(1-y)+6y=-3(y+4)

Solution for 2(1-y)+6y=-3(y+4) equation:

2(1-y)+6y=-3(y+4)

We move all terms to the left:

2(1-y)+6y-(-3(y+4))=0

We add all the numbers together, and all the variables

2(-1y+1)+6y-(-3(y+4))=0

We add all the numbers together, and all the variables

6y+2(-1y+1)-(-3(y+4))=0

We multiply parentheses

6y-2y-(-3(y+4))+2=0


We calculate terms in parentheses: -(-3(y+4)), so:

-3(y+4)

We multiply parentheses

-3y-12

Back to the equation:

-(-3y-12)


We add all the numbers together, and all the variables

4y-(-3y-12)+2=0

We get rid of parentheses

4y+3y+12+2=0

We add all the numbers together, and all the variables

7y+14=0

We move all terms containing y to the left, all other terms to the right

7y=-14

y=-14/7

y=-2