2(1-x)=10-(x+2)

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Solution for 2(1-x)=10-(x+2) equation: 



2(1-x)=10-(x+2)

We move all terms to the left:

2(1-x)-(10-(x+2))=0

We add all the numbers together, and all the variables

2(-1x+1)-(10-(x+2))=0

We multiply parentheses

-2x-(10-(x+2))+2=0



We calculate terms in parentheses: -(10-(x+2)), so:

10-(x+2)

determiningTheFunctionDomain
-(x+2)+10

We get rid of parentheses

-x-2+10

We add all the numbers together, and all the variables

-1x+8

Back to the equation:

-(-1x+8)



We get rid of parentheses

-2x+1x-8+2=0

We add all the numbers together, and all the variables

-1x-6=0

We move all terms containing x to the left, all other terms to the right

-x=6

x=6/-1

x=-6

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