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2(1-x)-4x=-(9x-2)+8x
We move all terms to the left:
2(1-x)-4x-(-(9x-2)+8x)=0
We add all the numbers together, and all the variables
2(-1x+1)-4x-(-(9x-2)+8x)=0
We add all the numbers together, and all the variables
-4x+2(-1x+1)-(-(9x-2)+8x)=0
We multiply parentheses
-4x-2x-(-(9x-2)+8x)+2=0
We calculate terms in parentheses: -(-(9x-2)+8x), so:We add all the numbers together, and all the variables
-(9x-2)+8x
We add all the numbers together, and all the variables
8x-(9x-2)
We get rid of parentheses
8x-9x+2
We add all the numbers together, and all the variables
-1x+2
Back to the equation:
-(-1x+2)
-6x-(-1x+2)+2=0
We get rid of parentheses
-6x+1x-2+2=0
We add all the numbers together, and all the variables
-5x=0
x=0/-5
x=0
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