2(1-3n)-4=3(2n+3)-n

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Solution for 2(1-3n)-4=3(2n+3)-n equation: 



2(1-3n)-4=3(2n+3)-n

We move all terms to the left:

2(1-3n)-4-(3(2n+3)-n)=0

We add all the numbers together, and all the variables

2(-3n+1)-(3(2n+3)-n)-4=0

We multiply parentheses

-6n-(3(2n+3)-n)+2-4=0



We calculate terms in parentheses: -(3(2n+3)-n), so:

3(2n+3)-n

We add all the numbers together, and all the variables

-1n+3(2n+3)

We multiply parentheses

-1n+6n+9

We add all the numbers together, and all the variables

5n+9

Back to the equation:

-(5n+9)



We add all the numbers together, and all the variables

-6n-(5n+9)-2=0

We get rid of parentheses

-6n-5n-9-2=0

We add all the numbers together, and all the variables

-11n-11=0

We move all terms containing n to the left, all other terms to the right

-11n=11

n=11/-11

n=-1

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