2(1-2v)+6=-4(v-2)

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Solution for 2(1-2v)+6=-4(v-2) equation: 



2(1-2v)+6=-4(v-2)

We move all terms to the left:

2(1-2v)+6-(-4(v-2))=0

We add all the numbers together, and all the variables

2(-2v+1)-(-4(v-2))+6=0

We multiply parentheses

-4v-(-4(v-2))+2+6=0



We calculate terms in parentheses: -(-4(v-2)), so:

-4(v-2)

We multiply parentheses

-4v+8

Back to the equation:

-(-4v+8)



We add all the numbers together, and all the variables

-4v-(-4v+8)+8=0

We get rid of parentheses

-4v+4v-8+8=0

We add all the numbers together, and all the variables

=0

v=0/1

v=0

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