2(1+r)-5=3r+7(r-5)

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Solution for 2(1+r)-5=3r+7(r-5) equation: 



2(1+r)-5=3r+7(r-5)

We move all terms to the left:

2(1+r)-5-(3r+7(r-5))=0

We add all the numbers together, and all the variables

2(r+1)-(3r+7(r-5))-5=0

We multiply parentheses

2r-(3r+7(r-5))+2-5=0



We calculate terms in parentheses: -(3r+7(r-5)), so:

3r+7(r-5)

We multiply parentheses

3r+7r-35

We add all the numbers together, and all the variables

10r-35

Back to the equation:

-(10r-35)



We add all the numbers together, and all the variables

2r-(10r-35)-3=0

We get rid of parentheses

2r-10r+35-3=0

We add all the numbers together, and all the variables

-8r+32=0

We move all terms containing r to the left, all other terms to the right

-8r=-32

r=-32/-8

r=+4

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