2(1+2n)+2n=5(n+2)=

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Solution for 2(1+2n)+2n=5(n+2)= equation:



2(1+2n)+2n=5(n+2)=
We move all terms to the left:
2(1+2n)+2n-(5(n+2))=0
We add all the numbers together, and all the variables
2(2n+1)+2n-(5(n+2))=0
We add all the numbers together, and all the variables
2n+2(2n+1)-(5(n+2))=0
We multiply parentheses
2n+4n-(5(n+2))+2=0
We calculate terms in parentheses: -(5(n+2)), so:
5(n+2)
We multiply parentheses
5n+10
Back to the equation:
-(5n+10)
We add all the numbers together, and all the variables
6n-(5n+10)+2=0
We get rid of parentheses
6n-5n-10+2=0
We add all the numbers together, and all the variables
n-8=0
We move all terms containing n to the left, all other terms to the right
n=8

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