2(0.5x-1)+22=2-0.4(x-1)

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Solution for 2(0.5x-1)+22=2-0.4(x-1) equation: 



2(0.5x-1)+22=2-0.4(x-1)

We move all terms to the left:

2(0.5x-1)+22-(2-0.4(x-1))=0

We multiply parentheses

0x-(2-0.4(x-1))-2+22=0



We calculate terms in parentheses: -(2-0.4(x-1)), so:

2-0.4(x-1)

determiningTheFunctionDomain
-0.4(x-1)+2

We multiply parentheses

-0.4x+0.4+2

We add all the numbers together, and all the variables

-0.4x+2.4

Back to the equation:

-(-0.4x+2.4)



We add all the numbers together, and all the variables

x-(-0.4x+2.4)+20=0

We get rid of parentheses

x+0.4x-2.4+20=0

We add all the numbers together, and all the variables

1.4x+17.6=0

We move all terms containing x to the left, all other terms to the right

1.4x=-17.6

x=-17.6/1.4

x=-12+0.8/1.4

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