2(-c+11)=10

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Solution for 2(-c+11)=10 equation: 



2(-c+11)=10

We move all terms to the left:

2(-c+11)-(10)=0

We add all the numbers together, and all the variables

2(-1c+11)-10=0

We multiply parentheses

-2c+22-10=0

We add all the numbers together, and all the variables

-2c+12=0

We move all terms containing c to the left, all other terms to the right

-2c=-12

c=-12/-2

c=+6

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