2(-b-c)+2b-4c=0

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Solution for 2(-b-c)+2b-4c=0 equation:


Simplifying
2(-1b + -1c) + 2b + -4c = 0
(-1b * 2 + -1c * 2) + 2b + -4c = 0
(-2b + -2c) + 2b + -4c = 0

Reorder the terms:
-2b + 2b + -2c + -4c = 0

Combine like terms: -2b + 2b = 0
0 + -2c + -4c = 0
-2c + -4c = 0

Combine like terms: -2c + -4c = -6c
-6c = 0

Solving
-6c = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Divide each side by '-6'.
c = 0

Simplifying
c = 0

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