2(-7r-4)-3r=-3(4+4r)-r

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Solution for 2(-7r-4)-3r=-3(4+4r)-r equation: 



2(-7r-4)-3r=-3(4+4r)-r

We move all terms to the left:

2(-7r-4)-3r-(-3(4+4r)-r)=0

We add all the numbers together, and all the variables

2(-7r-4)-3r-(-3(4r+4)-r)=0

We add all the numbers together, and all the variables

-3r+2(-7r-4)-(-3(4r+4)-r)=0

We multiply parentheses

-3r-14r-(-3(4r+4)-r)-8=0



We calculate terms in parentheses: -(-3(4r+4)-r), so:

-3(4r+4)-r

We add all the numbers together, and all the variables

-1r-3(4r+4)

We multiply parentheses

-1r-12r-12

We add all the numbers together, and all the variables

-13r-12

Back to the equation:

-(-13r-12)



We add all the numbers together, and all the variables

-17r-(-13r-12)-8=0

We get rid of parentheses

-17r+13r+12-8=0

We add all the numbers together, and all the variables

-4r+4=0

We move all terms containing r to the left, all other terms to the right

-4r=-4

r=-4/-4

r=1

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