2(-6x+11)-42=10(-x-2)-8

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Solution for 2(-6x+11)-42=10(-x-2)-8 equation: 



2(-6x+11)-42=10(-x-2)-8

We move all terms to the left:

2(-6x+11)-42-(10(-x-2)-8)=0

We add all the numbers together, and all the variables

2(-6x+11)-(10(-1x-2)-8)-42=0

We multiply parentheses

-12x-(10(-1x-2)-8)+22-42=0



We calculate terms in parentheses: -(10(-1x-2)-8), so:

10(-1x-2)-8

We multiply parentheses

-10x-20-8

We add all the numbers together, and all the variables

-10x-28

Back to the equation:

-(-10x-28)



We add all the numbers together, and all the variables

-12x-(-10x-28)-20=0

We get rid of parentheses

-12x+10x+28-20=0

We add all the numbers together, and all the variables

-2x+8=0

We move all terms containing x to the left, all other terms to the right

-2x=-8

x=-8/-2

x=+4

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