2(-6-7b)+2(1-3b)=50

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Solution for 2(-6-7b)+2(1-3b)=50 equation: 



2(-6-7b)+2(1-3b)=50

We move all terms to the left:

2(-6-7b)+2(1-3b)-(50)=0

We add all the numbers together, and all the variables

2(-7b-6)+2(-3b+1)-50=0

We multiply parentheses

-14b-6b-12+2-50=0

We add all the numbers together, and all the variables

-20b-60=0

We move all terms containing b to the left, all other terms to the right

-20b=60

b=60/-20

b=-3

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