2(-5-x)-5x=3-2(2+x)

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Solution for 2(-5-x)-5x=3-2(2+x) equation: 



2(-5-x)-5x=3-2(2+x)

We move all terms to the left:

2(-5-x)-5x-(3-2(2+x))=0

We add all the numbers together, and all the variables

2(-1x-5)-5x-(3-2(x+2))=0

We add all the numbers together, and all the variables

-5x+2(-1x-5)-(3-2(x+2))=0

We multiply parentheses

-5x-2x-(3-2(x+2))-10=0



We calculate terms in parentheses: -(3-2(x+2)), so:

3-2(x+2)

determiningTheFunctionDomain
-2(x+2)+3

We multiply parentheses

-2x-4+3

We add all the numbers together, and all the variables

-2x-1

Back to the equation:

-(-2x-1)



We add all the numbers together, and all the variables

-7x-(-2x-1)-10=0

We get rid of parentheses

-7x+2x+1-10=0

We add all the numbers together, and all the variables

-5x-9=0

We move all terms containing x to the left, all other terms to the right

-5x=9

x=9/-5

x=-1+4/5

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