2(-4v-8)+26=5(-7v-11)+11

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Solution for 2(-4v-8)+26=5(-7v-11)+11 equation:



2(-4v-8)+26=5(-7v-11)+11
We move all terms to the left:
2(-4v-8)+26-(5(-7v-11)+11)=0
We multiply parentheses
-8v-(5(-7v-11)+11)-16+26=0
We calculate terms in parentheses: -(5(-7v-11)+11), so:
5(-7v-11)+11
We multiply parentheses
-35v-55+11
We add all the numbers together, and all the variables
-35v-44
Back to the equation:
-(-35v-44)
We add all the numbers together, and all the variables
-8v-(-35v-44)+10=0
We get rid of parentheses
-8v+35v+44+10=0
We add all the numbers together, and all the variables
27v+54=0
We move all terms containing v to the left, all other terms to the right
27v=-54
v=-54/27
v=-2

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