2(-48-b)+b=-11

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Solution for 2(-48-b)+b=-11 equation: 



2(-48-b)+b=-11

We move all terms to the left:

2(-48-b)+b-(-11)=0

We add all the numbers together, and all the variables

2(-1b-48)+b-(-11)=0

We add all the numbers together, and all the variables

b+2(-1b-48)+11=0

We multiply parentheses

b-2b-96+11=0

We add all the numbers together, and all the variables

-1b-85=0

We move all terms containing b to the left, all other terms to the right

-b=85

b=85/-1

b=-85

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