2(-3z+1)=40

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Solution for 2(-3z+1)=40 equation: 



2(-3z+1)=40

We move all terms to the left:

2(-3z+1)-(40)=0

We multiply parentheses

-6z+2-40=0

We add all the numbers together, and all the variables

-6z-38=0

We move all terms containing z to the left, all other terms to the right

-6z=38

z=38/-6

z=-6+1/3

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