2(-3y-5)=3y+8

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Solution for 2(-3y-5)=3y+8 equation: 



2(-3y-5)=3y+8

We move all terms to the left:

2(-3y-5)-(3y+8)=0

We multiply parentheses

-6y-(3y+8)-10=0

We get rid of parentheses

-6y-3y-8-10=0

We add all the numbers together, and all the variables

-9y-18=0

We move all terms containing y to the left, all other terms to the right

-9y=18

y=18/-9

y=-2

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