2(-3+6z)=42

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Solution for 2(-3+6z)=42 equation: 



2(-3+6z)=42

We move all terms to the left:

2(-3+6z)-(42)=0

We add all the numbers together, and all the variables

2(6z-3)-42=0

We multiply parentheses

12z-6-42=0

We add all the numbers together, and all the variables

12z-48=0

We move all terms containing z to the left, all other terms to the right

12z=48

z=48/12

z=4

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