2(-3+2)=-5(r-3)

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Solution for 2(-3+2)=-5(r-3) equation: 



2(-3+2)=-5(r-3)

We move all terms to the left:

2(-3+2)-(-5(r-3))=0

We add all the numbers together, and all the variables

-(-5(r-3))+2(-1)=0

We add all the numbers together, and all the variables

-(-5(r-3))-2=0



We calculate terms in parentheses: -(-5(r-3)), so:

-5(r-3)

We multiply parentheses

-5r+15

Back to the equation:

-(-5r+15)



We get rid of parentheses

5r-15-2=0

We add all the numbers together, and all the variables

5r-17=0

We move all terms containing r to the left, all other terms to the right

5r=17

r=17/5

r=3+2/5

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