2(-2z+3)=-2(3z+2)

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Solution for 2(-2z+3)=-2(3z+2) equation: 



2(-2z+3)=-2(3z+2)

We move all terms to the left:

2(-2z+3)-(-2(3z+2))=0

We multiply parentheses

-4z-(-2(3z+2))+6=0



We calculate terms in parentheses: -(-2(3z+2)), so:

-2(3z+2)

We multiply parentheses

-6z-4

Back to the equation:

-(-6z-4)



We get rid of parentheses

-4z+6z+4+6=0

We add all the numbers together, and all the variables

2z+10=0

We move all terms containing z to the left, all other terms to the right

2z=-10

z=-10/2

z=-5

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