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2(-2x^2)-3x+3=0
We multiply parentheses
-4x^2-3x+3=0
a = -4; b = -3; c = +3;
Δ = b2-4ac
Δ = -32-4·(-4)·3
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{57}}{2*-4}=\frac{3-\sqrt{57}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{57}}{2*-4}=\frac{3+\sqrt{57}}{-8} $
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