2(-2-5y)=-(8y+2)

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Solution for 2(-2-5y)=-(8y+2) equation: 



2(-2-5y)=-(8y+2)

We move all terms to the left:

2(-2-5y)-(-(8y+2))=0

We add all the numbers together, and all the variables

2(-5y-2)-(-(8y+2))=0

We multiply parentheses

-10y-(-(8y+2))-4=0



We calculate terms in parentheses: -(-(8y+2)), so:

-(8y+2)

We get rid of parentheses

-8y-2

Back to the equation:

-(-8y-2)



We get rid of parentheses

-10y+8y+2-4=0

We add all the numbers together, and all the variables

-2y-2=0

We move all terms containing y to the left, all other terms to the right

-2y=2

y=2/-2

y=-1

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