2(-10z+3)=6-20z

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Solution for 2(-10z+3)=6-20z equation: 



2(-10z+3)=6-20z

We move all terms to the left:

2(-10z+3)-(6-20z)=0

We add all the numbers together, and all the variables

2(-10z+3)-(-20z+6)=0

We multiply parentheses

-20z-(-20z+6)+6=0

We get rid of parentheses

-20z+20z-6+6=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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